挑战排片数据排序为影片名称

main
rogersun 3 days ago
parent 6142614593
commit 8da98359d5
  1. 2
      ai/utils/basic_func.py

@ -155,7 +155,7 @@ def count_show(show_data):
show_dict[show['影片别名']] += 1 show_dict[show['影片别名']] += 1
else: else:
show_dict[show['影片别名']] = 1 show_dict[show['影片别名']] = 1
show_dict = dict(sorted(show_dict.items(), key=lambda item: item[1], reverse=True)) show_dict = dict(sorted(show_dict.items(), key=lambda item: item[0], reverse=True))
show_count = [] show_count = []
for show, count in show_dict.items(): for show, count in show_dict.items():
show_count.append(f"{show}{str(round(count / len(show_data) * 100, 2))}%,共排{str(count)}") show_count.append(f"{show}{str(round(count / len(show_data) * 100, 2))}%,共排{str(count)}")

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